|
|

楼主 |
发表于 2005-11-3 15:57
|
显示全部楼层
下面谈谈“均线密集”这个概念:
老股民多说:5日平均线和10日平均线和20日平均线多趋于一起,成本趋于一致,说明要变盘。
这话只对了一半,为什么?因为成本是一个区域,不能靠3个或4个平均价来说明该股票的成本就是它。
但这个想法是对的,就是用的方法不对。现在我们就用这个想法来选股票,那就是要挑那些成本区域很小的股票,一般在10%以内,最好在5%以内。我们应该关心它了。一旦向上突破最大成本,我们就可以先用10%-30%的资金先买一点。(因为它符合了“赚钱效应”这个条件,又符合了市场成本趋于一致,而现在正向上突破这三个条件),
为什么不满仓买呢?你又忘了前面我说的明天有可能回试的动作,还有假突破呢?
所以不能满仓买呢。
这样mma公式又可以改为如下:
公式名:mma (主图叠加)
ma2:=sum(AMOUNT/100,2)/sum(v,2);
ma3:=sum(AMOUNT/100,3)/sum(v,3);
ma4:=sum(AMOUNT/100,4)/sum(v,4);
ma5:=sum(AMOUNT/100,5)/sum(v,5);
ma6:=sum(AMOUNT/100,6)/sum(v,6);
ma7:=sum(AMOUNT/100,7)/sum(v,7);
ma8:=sum(AMOUNT/100,8)/sum(v,8);
ma9:=sum(AMOUNT/100,9)/sum(v,9);
ma10:=sum(AMOUNT/100,10)/sum(v,10);
ma11:=sum(AMOUNT/100,11)/sum(v,11);
ma12:=sum(AMOUNT/100,12)/sum(v,12);
ma13:=sum(AMOUNT/100,13)/sum(v,13);
ma14:=sum(AMOUNT/100,14)/sum(v,14);
ma15:=sum(AMOUNT/100,15)/sum(v,15);
ma16:=sum(AMOUNT/100,16)/sum(v,16);
ma17:=sum(AMOUNT/100,17)/sum(v,17);
ma18:=sum(AMOUNT/100,18)/sum(v,18);
ma19:=sum(AMOUNT/100,19)/sum(v,19);
a:max(ma2,max(ma3,max(ma4,max(ma5,max(ma6,max(ma7,max(ma8,max(ma9,max(ma10,
max(ma11,max(ma12,max(ma13,max(ma14,max(ma15,max(ma16,max(ma17,
max(ma18,ma19))))))))))))))))),LINETHICK0;
b:min(ma2,min(ma3,min(ma4,min(ma5,min(ma6,min(ma7,min(ma8,min(ma9,min(ma10,
min(ma11,min(ma12,min(ma13,min(ma14,min(ma15,min(ma16,min(ma17,
min(ma18,ma19))))))))))))))))),LINETHICK0;
sum(AMOUNT/100,2)/sum(v,2),color0000ff;
sum(AMOUNT/100,3)/sum(v,3),color888888;
sum(AMOUNT/100,4)/sum(v,4),color888888;
sum(AMOUNT/100,5)/sum(v,5),color888888;
sum(AMOUNT/100,6)/sum(v,6),color888888;
sum(AMOUNT/100,7)/sum(v,7),color888888;
sum(AMOUNT/100,8)/sum(v,8),color888888;
sum(AMOUNT/100,9)/sum(v,9),color888888;
sum(AMOUNT/100,10)/sum(v,10),color888888;
sum(AMOUNT/100,11)/sum(v,11),color888888;
sum(AMOUNT/100,12)/sum(v,12),color888888;
sum(AMOUNT/100,13)/sum(v,13),color888888;
sum(AMOUNT/100,14)/sum(v,14),color888888;
sum(AMOUNT/100,15)/sum(v,15),color888888;
sum(AMOUNT/100,16)/sum(v,16),color888888;
sum(AMOUNT/100,17)/sum(v,17),color888888;
sum(AMOUNT/100,18)/sum(v,18),color888888;
sum(AMOUNT/100,19)/sum(v,19),color888888;
mah:max(ma2,max(ma3,max(ma4,max(ma5,max(ma6,max(ma7,max(ma8,max(ma9,max(ma10,
max(ma11,max(ma12,max(ma13,max(ma14,max(ma15,max(ma16,max(ma17,
max(ma18,ma19))))))))))))))))),LINETHICK2,color00ff00;
mal:min(ma2,min(ma3,min(ma4,min(ma5,min(ma6,min(ma7,min(ma8,min(ma9,min(ma10,
min(ma11,min(ma12,min(ma13,min(ma14,min(ma15,min(ma16,min(ma17,
min(ma18,ma19))))))))))))))))),LINETHICK2,color00ff00;
DRAWICON(cross(c,mah),l ,4);
DRAWICON(((a-b)/b)*100<10 and cross(c,mah),h+0.01,7);
这个公式加了2个指示尖头,下面的尖头表示向上突破成本区域,上面的尖头表示向上突破密集成本区域,哈哈大家试试吧!
[ Last edited by glpjy on 2005-11-3 at 16:01 ] |
|
|